Quiz: Quiz Chapter 6 This Question: 1 pt 17 of 24 This Quiz: 24 pts possi Use th
ID: 3355760 • Letter: Q
Question
Quiz: Quiz Chapter 6 This Question: 1 pt 17 of 24 This Quiz: 24 pts possi Use the sandar mom distributor o the distribution to construct a % confidence interval for the op lat on mean. Just y your decision. I neither distribution In a random sample of 44 people, the mean body mass index (BMI) was 28.7 and the standard deviation was 6.04. can be used, explain why. Interpret the results. Which distribution should be used to construct the confidence interval? Choose the correct answer below O A. Use a normal distribution because the sample is random, the population is normal, and is known. O B. Use a normal distribution because the sample is random, n230, and is known. O c. Use a-distrbution because the sample is random, the population is normal, and is unknown. O D. Use a t-distribution because the sample is random, n 2 30, and o is unknown E. No era normal dsr bu on nora t distribu on can be used because ether the sampe s not random or nc30, and the population is not known to be no Seed the oorectchoice be ow and·if necessary, fil in any answer boxes to complete your choice 1 O A. The 90% confidence interval is ( Round to two decimal places as needed.) Neither distribution can be used to construct the confidence interval. O B. Interpret the results. Choose the correct answer belovw O A. lf a large sample of people are taken approxi mately 90% of them will have a BMI between the bounds of the confidence interval between the bounds of the confidence interval B. It can be said that 90% of people have a BMI O c. with 90% confdence, it can be said that 0 D. Neither distribution can be used to construct the confidence interval. the population mean BMI is between the bounds of the confidence interval Click to select your answer Save for LaterExplanation / Answer
The statistical software output for this problem is:
One sample T summary confidence interval:
: Mean of population
90% confidence interval results:
Hence,
Use a t - distribution; Option D is correct.
90% confidence interval is: (27.17, 30.23)
Interpretation: Option C is correct.
Mean Sample Mean Std. Err. DF L. Limit U. Limit 28.7 0.91056426 43 27.169277 30.230723Related Questions
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