Quiz: Quiz #16(Post-Irma): Section 6.3 [Unit 3] Time Remaining: 00:05:57 Submit
ID: 2926109 • Letter: Q
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Quiz: Quiz #16(Post-Irma): Section 6.3 [Unit 3] Time Remaining: 00:05:57 Submit Quiz This Question: 1 pt This Quiz s that an work table, the sitting knee height must be considered, which is the with a mean of 21.3 in. and a standard deviation of 1.3 in. Females have sitting knee heights that are normally distributed with a mean of 19.3 in. and a standard deviation of 1.2 in. Use this information to answer the following questions. in.(Round to one decimal place as needed.) O A. The statement is false because some women will have sitting knee heights that are outiliers. The statement is true because some women will have sitting knee heights that are outiers O C. The statement is true because the 95th percentle for men is greater than the 5th percentile for women O D. The statement is false because the 95th percentile for men is greater than the 5th percentile for women. %(Round to two decimal places as needed) What percentage of women fit this table? %(Round to two decimal places as needed) Does the table appear to be made to it almost everyone? Choose the correct answer below 8 4 [Unit 4 of unit test score 40min 10/15/17 here to searchExplanation / Answer
Params of normal disttribution for men:
Mean(men) = 21.3
Stdev (men) = 1.3
a. Min table clr. reqd for fitting 95% should be
P(-c<=X<=c) = .95.
So, Z value for area around mean of .95 is -1.96
So, (c-21.3)/1.3 = -1.96
c = -1.96*1.3+21.3 = 18.75
So, minimum table clearence required to satisfy the requirement of fitting 95% of men = 18.75
b.
C is right.
Essentially , we have check if the 95% clearence of men has overlap of 5% bottom women. If there is, then the statement is FALSE. Since, bottom 5% in women is given by 19.3-1.645*1.2 = 17.33 and for men the the minumum clearence for 95% of mean is 18.75. So, answer is option C. the statement is true because the 95th percentile for men is greater than the 5th percentile for women
c. P(X<=23.5)
= P(Z<=23.5-21.3/1.3)
= P(Z<=1.69)
=.9545
So, 95.45% of men will clear 23.5in
d.P(X<=23.5)
= P(Z<=23.5-19.3/1.2)
= P(Z<=3.5)
= ~ 100%
So, 95.45% of men will clear 23.5in
Yes, it does appear to fit almost everyone.
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