The probability that a tourist who is visiting Washington D.C. will visit the Wa
ID: 3354833 • Letter: T
Question
The probability that a tourist who is visiting Washington D.C. will visit the Washington Monument is .32. The probability that a tourist who is visiting Washington D.C will visit the Smithsonian is .52. The probability that a tourist who is visiting Washington D.C will visit the Washington Monument and visit the Smithsonian is .15. Compute
a) the probability that a tourist who is visiting Washington D.C will visit at least one of these two attractions.
b) the probability that a tourist who is visiting Washington D.C will visit the Washington Monument and will not visit the Smithsonian,
c) the probability that a tourist who is visiting Washington D.C will visit neither of the two attractions.
Explanation / Answer
let probability of visiting Washington Monument =P(A) =0.32
probability of visiting Smithsonian =P(B)=0.52
probability that a tourist will visit the Washington Monument and visit the Smithsonian =P(AnB) =0.15
a) probability that a tourist who is visiting Washington D.C will visit at least one of these two attractions
P(AUB) =P(A)+P(B)-P(AnB) =0.32+0.52-0.15=0.69
b)probability that a tourist who is visiting Washington D.C will visit the Washington Monument and will not visit the Smithsonian =P(A)-P(AnB) =0.32-0.15=0.17
c)
probability that a tourist who is visiting Washington D.C will visit neither of the two attractions
=1-P(AUB) =1-0.69 =0.31
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