A formula for justifying answers gotten simply by counting equally likely outcom

Question

A formula for justifying answers gotten simply by counting equally likely outcomes is P(A) = #(A) #(S) = number of outcomes in A number of outcomes in all. So the solution of the problem of finding the probability of getting an even number in one roll of a fair die would be written P(E) = #(E) #(S) = 3 6 = 0.5.

20. Assuming that the outcomes are equally likely, find the probability of each event in Exercise 18. Additional Exercises 21. The following two-way contingency table gives the breakdown of the population in a particular locale according to age and tobacco usage:

Explanation / Answer

21. doesn't have data, I think you are asking for an explanation for the formula written outside image:

This is correct.

No. of even faces on a dice = 3

No. of total faces on a dice = 6

Therfore, P(E) = No. of even faces/total faces on die = 3/6 = 1/2 = .50

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