The revenue equation (in hunderds of milions of dollars) for barley production i

Q: The revenue equation (in hunderds of milions of dollars) for barley production i

Ans: Marginal revenue is the derivative of the revenue function, so take the derivative of R(x). a)R'(x)=dR/dx=2*0.0686x+1.2347=0.1372x+1.2347 b)when x=200,000,000=2 hundred millions R'(2)=0.1372*2+1.2347=1.5091 c)when x=750,000,000=7.5 hundred millions R'(7.5)=0.1372*7.5+1.2347=2.2637

ID: 3353714 • Letter: T

Question

The revenue equation (in hunderds of milions of dollars) for barley production in a certain country is approximated by Rx)-0.0686x2+1.2347x2.2667 here x is in hundreds of millions of bushels. Find the marginal-evenue equation and use t to find the marginal revenue for the production of the given number of bushels. (a) The marginal-revenue equation is R'() (Round to four decimal places as needed.) (b) Find the marginal revenue for the production of 200,000,000 bushels. The marginal revenue is hundred million dollars. Type an integer or decimal rounded to two decimal places as needed.) (c) Find the marginal revenue for the production of 750,000,000 bushels. The marginal revenue ishundred million dollars Type an integer or decimal rounded to two decimal places as needed.)

Explanation / Answer

Ans:

Marginal revenue is the derivative of the revenue function, so take the derivative of R(x).

a)R'(x)=dR/dx=2*0.0686x+1.2347=0.1372x+1.2347

b)when x=200,000,000=2 hundred millions

R'(2)=0.1372*2+1.2347=1.5091

c)when x=750,000,000=7.5 hundred millions

R'(7.5)=0.1372*7.5+1.2347=2.2637

Navigate

The revenue equation (in hunderds of imiliors af dolars) or barley producton in

The revenue equation (in hunderds of millions of dollars) for barley production

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

The revenue equation (in hunderds of milions of dollars) for barley production i

Question

Explanation / Answer

Related Questions

Navigate