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The results of the experiment were: 50ml-27.3s 35ml-40s 25ml-60.5s 15ml-123.1s 5

ID: 569696 • Letter: T

Question


The results of the experiment were: 50ml-27.3s 35ml-40s 25ml-60.5s 15ml-123.1s 50ml-27.3s 35ml-40s 25ml-60.5s 15ml-123.1s
What are the relative rates of reaction for each reaction with different volume of sodium thiosulphate?
1. Measure 50ml of sodium thiosulphate into the 50ml measuring cylinder and then add it to the beaker 2. Place the conical flask/beaker on a paper given 3. Record the initial temperature of the sodium thiosulphate solution 4. Measure 25 ml of 0.5M HCl into a 25ml measuring cylinder 5. Add the HCl to the conical beaker and immediately start timing 6. Swirl the contents of the flask/beaker once and let it stand on the white tile 7. Stop timing when the writing on the paper is no longer visible through the solution 8. Record the time taken in seconds 9. Wash the solution down the sink with plenty of water 10. Repeat the experiment at three different concentrations of sodium thiosulphate (refer to the results table) 11. Use 1/time taken as a measure of the relative rate Expt. Volume of 0.15M Volume of Volume of Concentration Time Relative of thiosulphate taken/s rate/s solution/NM sodium thiosulphate/ml water/ml 50 35 25 15 distilled HCVml 15 25 35 25 25 25 25 N.B. Add the required volume of thiosulphate to the 50ml measuring cylinder and then make it up to the 50 ml mark with distilled water, where applicable.

Explanation / Answer

This is very easy. What you need to do is just calculate 1/time and that is the result because it is a first order reaction with respect to Na2S2O3

Expt. Time taken (sec) relative rate (s-1) 1. 27.3 0.0366 2. 40 0.025 3. 60.5 0.0165 4. 123.1 0.0081
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