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. Measure of error-For the following two sets of data, test for possible outlier

ID: 3352477 • Letter: #

Question

. Measure of error-For the following two sets of data, test for possible outliers. If you ind an outlier, eliminate it from the data set and then find the mean, the standard deviation, the relative standard deviation, and the percent relative standard deviation. The appropriate critica Dixon's Q values are provided: # of data points Critical Q 831 717 10 4 621 570 524492464 value Set A) 0.0774, 0.0844, 0.0882, 0.0811, 0.0864, 0.0825 Set B) 12.3, 11.8, 16.5, 12.6, 13.1, 11.9, 12.4, 12.7 Part 2. Accuracy calculation Given that the true' value for Part 1, Set A, is 0.0850 and the 'true' value for Part 1, Set B, is 12.5, calculate the percent relative accuracy for both data sets.

Explanation / Answer

Set A :

0.0774, 0.0844, 0.0882, 0.0811, 0.0864, 0.0825

making it ascending

0.0774, 0.0811, 0.0825 , 0.0844,0.0864, 0.0882

Here Q = gap/ range = (0.0811 - 0.0774)/ (0.0882 - 0.0774) = 0.3426

now this Q value is less than the critical value is 0.621 for n = 6 so we say that there is no outlier.

Set B:

12.3, 11.8, 16.5, 12.6, 13.1, 11.9, 12.4, 12.7

making it ascending in order

11.8, 11.9, 12.3, 12.4, 12.6, 12.7, 13.1, 16.5

here

Q = (16.5 - 13.1)/ (16.5 - 11.8) = 0.723

now this Q value is less than the critical value is 0.524 for n = 8 so we say that 16.5 is an outlier.

Old New Average 12.9125 12.4 Std. Dev. 1.5094 0.4546 Relative standard deviation 0.1169 0.0367 percent relaive standard deviation 11.6897 3.6662