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Question

. McNeese State Universit × ,' www.saplinglearning.con × www.saplinglearning co ×? AUniform Rod is Set Up × > ? } D www.saplinglearning.com/ibiscms/mod/ibis/view.php?id-5908382 Digital Resources for Supreme New Sapling Learning macmillan learning Sapling Learning McNeese State University - PHYS 211 - Summer18- STINNETTActivities and Due Dates HW: Dynamics of Rotational Motion My Assignment o 7/23/2018 10:00 PM?30/100?7/21/2018 04:13 PM Gradebook #Attempts Score Print Calculator l-d Periodic Table Question 8 of 10 Map da 100 Sapling Learning 100 A horizontal circular platform rotates counterclockwise about its axis at the rate of 0.847 rad/s. You, with a mass of 70.1 kg, walk clockwise around the platform along its edge at the speed of 1.15 m/s with respect to the platform. Your 20.1-kg poodle also walks clockwise around the platform, but along a circle at half the latform's radius and at half your linear speed with respect to the platform. Your 19.1-kg mutt, on the other and, sits still on the platform at a position that is 3/4 of the platform's radius from the center. Model the platform as a uniform disk with mass 90.7 kg and radius 1.83 m. Calculate the total angular momentum of 4 the system Number 10 Previous O check Answer ? Next- Exit Hint Type here to search

Explanation / Answer

For platform:

I=(1/2)MR2

I=(1/2)(90.7)(1.83)2

I=151.8726 Kgm^2

L=I?=(151.8726)(.847)

L=128.636 kgm^2/s

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For person

I=MR2

I=70.1(1.83)2

I=234.758

L=I?=(234.758)(.847-1.15/1.83)

L= 51.31 km^2/s

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For poodle

I=MR2

I=20.1(1.83/2)2

I=16.828 kgm^2

L=I?=(16.828)(.847-1.15/1.83)

L=3.678 kgm^2/s

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For mutt

I=MR2

I=19.1(3/4*1.83)2

I=35.98 kgm^2

L=I?=(35.98)(.847)

L=30.475 kgm^2/s

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Net angular momentum of system

Lsystem=30.475+3.687+51.31+128.636

Lsystem= 214.1 kg m2/s (counter clockwise). (Ans)