mework Assignment #2 Seved Help Save & Exit Submit Check my work 7 In a certain

Question

mework Assignment #2 Seved Help Save & Exit Submit Check my work 7 In a certain section of Southern Calfornia, the distribution of monthly rent for a one-bedroom apartment has a mean of $2.175 and a standard deviation of $250. The distribution of the monthly rent does not follow the normal distribution. In fact, it is positively skewed. 2 5 oints What is the probability of selecting a sample of 70 one-bedroom apartments and finding the mean to be at least $2.115 per month? (Round your z values to 2 decimal places and final answers to 4 decimal places.) eBook Reterences 5:34 PM

Explanation / Answer

=2175

=250

n=70

x=2115

z=(x-)/(/n)

=(2115-2175)/(250/70)

=-60/29.88

=-2.01

P(x>2115) =P(z>-2.01)

               = 1- P(z<-2.01)

               = 1- 0.0222

               =0.9778

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.