mers o an amusement park se ected a random sample and recorded the mumber of par
ID: 3369012 • Letter: M
Question
mers o an amusement park se ected a random sample and recorded the mumber of park patrons 7th annua passee eho r sited the ark on each se lected day. They compared a 90% confidence mten a tor the number o patrons h annual asses isit the park daily. How wonld von interpret the 90% nonfidence interval of (35, 51)? O a. Ten percent of the pepulation of annual pass holders ist the park on any piven day b. Thern a go% chance that tha sample percentage of park patrons with annual passesis contained in the interval 35 to 51. c. There is a 90% dance that the population mean number t Datons with annual passes who are in the park on any given day is between 25 and 51. d. The method used to calculate the cor dence interval has a 90% chance of p ducn ? an inter that cap res the population mean number of annual pass holders in the park on any given day.Explanation / Answer
From sample data we draw conclusion for population.
From sample data we find confidence interval for population mean.
Hence there is 90% chance that the population mean number of patrons with annual passes who are in the park in any given day is between ( 35 , 51 )
Hence "C" is the correct answer.
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