1. The following table provides chart data for the patients in a particular hosp
ID: 3350919 • Letter: 1
Question
1.The following table provides chart data for the patients in a particular hospital ward:
Patient Room # Physician Condition Length of stay
Carter, M. 202 Pollock Critical 8 days
Levin, J. 203 McClare Fair 4 days
Fox, J. 203 Lench Good 5 days
Garcia, L. 205 Lench Fair 7 days
Arluke, A. 201 Pollock Serious 2 days
Parodi, A. 203 McClare Good 9 days
Stark, D. 204 Lench Fair 5 days
Chow, F. 202 Pollock Critical 1 day
McDevitt, J. 204 Loftus Serious 2 days
Name and calculate the most appropriate measure of central tendency and variability for each of the following variables. Feel free to provide a justification for your choice of measure as you see fit
(4pts—0.25 points for each answer).
Room number
Measure of central tendency:
Central tendency value:
Measure of variability:
Variability value:
Physician
Measure of central tendency:
Central tendency value:
Measure of variability:
Variability value:
Patient condition
Measure of central tendency:
Central tendency value:
Measure of variability:
Variability value:
Length of hospital stay
Measure of central tendency:
Central tendency value:
Measure of variability:
Variability value:
2.A researcher collected information on the number of text messages sent over a 4-hour period by a group of teenagers and a group of parents. The data collected are as follows:
TEENAGERS
PARENTS
Case #
Number of texts
Case #
Number of texts
1
14
1
0
2
9
2
12
3
20
3
15
4
16
4
8
5
15
5
19
6
14
6
11
7
36
7
7
8
27
8
19
9
19
9
8
10
5
Find the mode, median, mean, range, and standard deviation for the number of texts sent by each group (teenagers and parents) (2.5pts—0.25pts for each answer).
TEENAGERS
PARENTS
MODE
MODE
MEDIAN
MEDIAN
MEAN
MEAN
RANGE
RANGE
STANDARD DEVIATION
STANDARD DEVIATION
Which group – teenagers or parents – tended to send more texts? Support your answer using statistics you calculated for Part a. [Choose the most useful statistics for making your case](0.5pts).
Which group – teenagers or parents – had the greatest diversity in the number of texts sent? Support your answer using statistics you calculated for Part a. [Choose the most useful statistics for making your case] (0.5pts).
What do your calculations indicate about the shape (symmetrical, negatively/left skewed, or positively/right skewed) of the distributions for the two groups? (0.25pts).
If you removed the most extreme case (the person with the most text messages) from each of the distributions, would your answers to Parts b and c change? (0.5pts)
3.A teacher is interested in understanding her students’ screen time. She asks a sample of her junior high school students how many hours they spent watching television or playing on their computers or phones during the previous weekend. The results of the survey are summarized in the following frequency distribution.
Hours of TV
Frequency
13
1
12
2
11
3
10
2
9
5
8
6
7
3
6
9
5
3
4
3
3
2
2
1
1
1
0
1
Calculate the following statistics to describe these data (1.75pts-0.25 pts each).
Mode:
First quartile:
Median:
Third quartile
Mean:
Range:
Standard deviation:
TEENAGERS
PARENTS
Case #
Number of texts
Case #
Number of texts
1
14
1
0
2
9
2
12
3
20
3
15
4
16
4
8
5
15
5
19
6
14
6
11
7
36
7
7
8
27
8
19
9
19
9
8
10
5
Explanation / Answer
Solution1:
we can measure room number.
median is central tendency as it is not affected by outiers.
code in R to find median and standard deviation.
Room <- c(202,203,203,205,201,203,204,202,204)
median(Room)
sd(Room)
Room number
Measure of central tendency: Median
Central tendency value: 203
Measure of variability: standard deviation
Variability value: 1.224745
We can count the number of physicians .central tendency is mode
Physician
Measure of central tendency: mode
Central tendency value: pollock ,lench
measuring dspersion is not important for nominal or ordinal variables.
Measure of variability:
Variability value:
Patient condition
Fair repeats 3 times.mode is 3
Measure of central tendency: mode
Central tendency value: Fair
measuring dspersion is not important for nominal or ordinal variables.
Measure of variability:
Variability value:
Length of hospital stay
we can measure length of hospital stay
code in R:
lengthofstay <- c(8,4,5,7,2,9,5,1,2)
median(lengthofstay)
sd(lengthofstay)
Measure of central tendency: median
Central tendency value: 5 ,
Measure of variability: standard deviation
Variability value: 2.818589
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