caloric intake (cal) 1873 2016 2295 2765 2154 2404 3018 total step dist (km) 2.5

Question

caloric intake (cal) 1873 2016 2295 2765 2154 2404 3018 total step dist (km) 2.5 3.7 2.3 1.1 2.2 1.7 0.4 The above table contains caloric intake (in calories) with corresponding total step distance covered (in km) in a 24 hr. period for a sample of 7 persons in a recent study. Assuming a significant linear correlation exists, use regression line equation to predict a total step distance in one day covered by a person who ingests 2545 calories on that day. Select one: O a. 2.6 O b. 0.9 c. 2.1 O d. 1.6 e. 1.2

Explanation / Answer

y = total step dist, x = calorie intake. The regression equation is of the form: y = b0 + (b1 * x).

b1 = cov(x,y)/var(x) = - 0.0023
b0 = mean(y) - (b1 * mean(x)) = 7.455

The regression equation is: y = - 0.0023 + (7.455 * x).

Putting x = 2545, we get y = 1.6 (Option d).

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