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Name with their mu. Name appropriate circuit diagram for the voltmeter? A) 1 B)

ID: 3349356 • Letter: N

Question

Name with their mu. Name appropriate circuit diagram for the voltmeter? A) 1 B) 2 C) 3 D) 4 E) 5 15. In the figure, when the terminal voltage Vab of the battery is equal to 20 V, how much current passes through the battery, including its direction? A) 4 A, from a to b B) 5 A, from a to b C) 6 A, from a to b D) 4 A, from b to a E) 5 A, from b to a 1 12 V 2.0 a+SWT 90.00 380.00 3 90olo 16. For the circuit shown in the figure, what current does the ideal ammeter read? A) 0.033 A B) 0.078 A C) 0.23 A D) 0.12 A 100v 30V 28000 Equations: = n, Av, 1--ei, = nedv, J = current density -- nev, v, - E J=0E 0 - ner p=1 E AP (Ohm's law) R= (relationship between resistance and resistivity) V. =E-Ir (terminal voltage, source with internal resistance) P = Is (power delivered by an emf) P = IAV, = I'R = a (power dissipated by a resistor) Reg = R + R2 + Rg + ... + Ry (series resistors) Reg= G + + (parallel resistors) EI=0 junction rule, valid at any junction) EV = 0 (loop rule, valid for any closed loop) g=CE (1-e**)=0,(1-e) (R-C circuit, charging capacitor) i-da-E, ARC = le RC (R-C circuit, charging capacitor) q=0.8 RC (R-C circuit, discharging capacitor) dq - 0,4RC = Lenc (R-C circuit, discharging capacitor) T= RC i- RC Page 3 of 4

Explanation / Answer

15) apply kvl

Current flow in the circuit is

I = (20-12)/2 = 4 A, in the direction a to b.

Option:- A

16) As we know voltage is same in parallel branches.

Voltage across 90 ohm resistor will be 3.0 V, since ammeter is ideal and no voltage drop across it

Current through ammeter is = 3/90 = 1/30 = 0.033 A.

Option :- A

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