4(a) 4(b) Your Mark: 4(a) 4(b) 4(a) 4(b) 4(b) 4(a) 4(b) roblem # 5: 44% of all p

Question

4(a) 4(b) Your Mark: 4(a) 4(b) 4(a) 4(b) 4(b) 4(a) 4(b) roblem # 5: 44% of all pets sold at a pet store are dogs. One day, 9 people arrive at the store and purchase pets. Note: One pet is purchased per person.) (a) What is the probability that exactly 5 of them are dogs? (b) If the store has only 7 dogs, what is the probability that they have sufficient dogs for sale that day? Problem #5(a): 10.20 Round your answer to 4 decimals. Problem #5(b): Round your answer to 4 decimals. Just Save Your work has been saved! (Back-to-AdminPaget Submit Problem #5 for Grading | Problem #5 | Attempt #2 5(a) 5(b) 5(a) 5(b) Attempt #1 Attempt #3 S(a) S(b) Your Answer: 5(a) 5(b) Your Mark: 5(a) 5(b) S(a) roblem #6: A die is rolled 30 times, and the value on top of the die recorded. 3

Explanation / Answer

n = 9

p = 0.44

q = 1 - p = 0.56

P(X) = nCx px qn-x

a) P(exactly 5 are dogs) = P(X = 5)

= 9C5 x 0.445 x 0.564

= 0.2044

b) P(they will have sufficient dogs) = P(demand is less than or equal to 7)

= 1 - P(X > 7)

= 1 - P(8) - P(9)

= 1 - 9x0.448x0.56 - 0.449

= 1 - 0.0071 - 0.0006

= 0.9923

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