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000 AT&T; LTE 2:26 PM 91% mathxl.com Wei Shop Youn. Welcome t... Ims.ssc.ed... McGraw-H Ims.ssc.ed Homework Do Hom MTH 126-301, Fall 2017 Lisa Koscielski 11/2/17 2:25 PM Review Homework: Section 6.2 Homework (a) Score: 2 of 3 pts 12 of 13 Hw Score: 97.5%, 39 of 40 pts 6.2.29 Question Help appro mately According to a recent study the average length of a newborn baby is 18.6 inches with a standard devation of 0.6 inch. The distribution of lenghs Normal. Complebe parts (a) through (c) below Include a Normal curve for each part a. What is the probability that a baby will have a length of 19 2 inches or more? Choose the Normal curve that repeesents the probability that a baby wil have a length of 19 2 inches or more. OA. B. The probability that a baby will have a length of 19.2 inches or more is 0.159 Type an integer or decimal rounded to hree decimal places as needed.) b. What is the probability that a baby will have a length of 19.8 inches or more? Choose the Normal curve that repeesents the probability that a baby will have a length of 19 inches or more OA. B. C. O D. The probability that a baby will have a length of 19.8 inches or moee is 0.023 Type an integer or decimal rounded to three decimal places as needed.) C. what the probablity that a baby wil have a length between 17.7 and 19.5 inches? Choose the Normal curve that represents the probabRy that a baby wil have a length between 17.7 and 19.5 inches O B. O D The probabillty that a baby will have a length between 17.7 and 19.5 inches is 0.866 Type an infeger or decimal rounded to three decimal places as needed.) Question is complete. Tap on the red indicators to see incormect answers Simlar QuestionExplanation / Answer
a. z-score = (19.2-18.6)/0.6 = 1
The graph in c is correct as P(X>=19.2) is the area on the right of z=1 which is 0.159.
b. z-score = (19.8-18.6)/0.6 = 2
The graph in c is correct as P(X>=19.8) is the area on the right of z=1 which is 0.023.
c. The graph in c is correct as P(17.7<=X<=19.5) = 0.866 is the area between z-scores (17.7-18.6)/0.6 = -1.5 and (19.5-18.6)/0.6 = 1.5.
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