You need to estimate the mean number of travel days per year for salespeople. Th

Question

You need to estimate the mean number of travel days per year for salespeople. The mean of a small pilot study was 150 days, with a standard deviation of 32 days. If you must estimate the population mean within 5 days, how many salespeople should you sample? Use the 95% confidence level. (Use (Round your answer to the next whole number.) mber of outside salespeople fz-1.96, then PO to z) 0.4750 0.0160 00557 .0948 00279 0.0675 0.1064 0.0319 0.0040 0.0438 0.0832 0.0120 0.0517 0.0359 .0753 0.0199 0.0910 0.1664 0.2019 0.1517 0.1879 0.1628 01844 0.5 0.7 0.9 0.2088 02123 033150.307830.2549 0.2852 0.3133 0.3621 0.2517 .2389 0.2704 0 2580 0 2881 0 2764 0.3051 0.2611 0.2794 0.2967 86 0.3212 0.32640.3023 0.3238 0.2995 0734 0245402157 0.3413 0.3849 04192 0.3485 0 3686 0.3888 0.3685 03790 03980 0 4147 04292 .3749 0.4015 0.4177 0.4319 03982 0.3925 0.4099 0.4207 0.4394 0.4505 04345 0.4463 04564 04649 0.4370 0.4484 04418 04616 0.4756 0.4382 0.4441 0.4429 0.4535 0.4625 0.4699 04515 0.4664 0.4726 0.4744 0.4817 0.4857 0.4788 0.4834 0.4871 0.4901 0.4925 0.4812 0.4854 0.4887 0.4913 0.4934 0.4778 0.4826 0.4830 0.4850 0.4821 0.4861 0.4842 0.4878 0.4846 04881 2.3 0.4896 0.4920 0.4904 0.4927 04911 04932 04918 0.4922 .4929 04931 0.4936 2.5 04955 04988 0.4975 0 4966 0.4967 0.4960 0.4970 0 4981 0.4971 .4959 0.4964 0.4974 .4981 .4957 0.4963 0.4965 04972 2.7 28 0.4977 0.4980 0.4984 0 4987 04987 0 4987 0.4988 .4988 04989 04989 .4990

Explanation / Answer

Compute Sample Size  

n = (Z a/2 * S.D / ME ) ^2

Z/2 at 0.05% LOS is = 1.96 ( From Standard Normal Table )

Standard Deviation ( S.D) = 32

ME =5

n = ( 1.96*32/5) ^2

= (62.72/5 ) ^2

= 157.352 ~ 158

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.