The amount of money spent weekly on cleaning,maintenance,and repairs at a large

Question

The amount of money spent weekly on cleaning,maintenance,and repairs at a large restaurant was observed over a long period of time to be approximately normally distributed, with mean u=$617, and standard deviation £=$38 If $646 is budgeted for next week what is the probability that the amount of money spent will exceed the budget amount?(Use four decimal places) The amount of money spent weekly on cleaning,maintenance,and repairs at a large restaurant was observed over a long period of time to be approximately normally distributed, with mean u=$617, and standard deviation £=$38 If $646 is budgeted for next week what is the probability that the amount of money spent will exceed the budget amount?(Use four decimal places) If $646 is budgeted for next week what is the probability that the amount of money spent will exceed the budget amount?(Use four decimal places)

Explanation / Answer

mean i.e = 617

standard deviation i.e = 38

z value = (x -)/

z value for 646 is (646-617)/38 = 0.7632, corresponding p value using z table is 0.7773

so P(X<= 646) = 0.7773 => P(X > 646) = 1 - 0.7773 = 0.2227

P(X > 646) = 0.2227

probability that the amount of money spent will exceed the budget amount is 0.2227

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