7. An urn initially contains 5 red marbles and 7 blue marbles. Bored out of your

Question

7. An urn initially contains 5 red marbles and 7 blue marbles. Bored out of your mind, you decide to play a "game" that goes as follows. During each round, you randomly pull a marble out of the urn. If the marble you chose was red, you return the marble back into the urn along with 1 more blue marble. If the marble you chose was blue, you put the marble back into the urn along with 2 more red marbles. What is the probability that on the first round you drew a red marble and on the third round you drew a blue marble

Explanation / Answer

probabilty that on first round you drew a red marble and on third you drew a blue marble

=P( red then red and then blue marble+red then blue and then blue marble)

=(5/12)*(5/13)*(9/14)+(5/12)*(8/13)*(8/15)=0.2398

please revert for any clarification

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