AaBbCcDdEe AaBbCcDdEe AaBbCcDc Normal No Spacing Heading 1 Q1. Suppose our class

Question

AaBbCcDdEe AaBbCcDdEe AaBbCcDc Normal No Spacing Heading 1 Q1. Suppose our class is interested in the effectiveness of an on-campus initiative to reduce domestic violence. From a sample of 100 students provided by NIU Health Services, we find that the mean (average) number of visits due to domestic violence is 4.00 per month. The standard deviation from these data is 0.75 visits/month. Based on information from all U.S. college health clinics, we know that the national average is 4.25 domestic violence visits per month. A) Conduct the appropriate hypothesis test to determine if there is evidence oi a decrease in injuries due to domestic violence on cam pus since the initiative has started. Use0.05. 1) Hypotheses (1 point) 2) Compute the appropriate test statistic. Be sure to include all components, including the degrees of freedom if applicable. (2 points) 3) P-Value (1 points) H) Conclusion (3 parts) (1 points) B) Generate a 95% confidence interval for the mean number of domestic violence cases per month at university health clinics. (3 points) C) Give a one sentence interpretation of this confidence interval (2 point)

Explanation / Answer

(A)
1) Null and alternate hypothesis
H0: mu = 4.25
H1: mu < 4.25

2)
Test statistics, t = (4 - 4.25)/(0.75/sqrt(100)) = -3.333

3)
degrees of freedom = 99
p-value = 0.0006

4)
As p-value is less than significance level of 0.05, we reject the null hypothesis.

B)
SE = 0.75/sqrt(100) = 0.075
For 95% CI, t-value = 1.66
ME = 0.075*1.66 = 0.1245

Lower bound = 4 - 0.1245 = 3.8755
upper bound = 4 + 0.1245 = 4.1245

C)
Confidence interval indicates that there is 95% probability that mean of sample of 100 from the population will have mean withing the range of of (3.8755, 4.1245)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.