oo Ooredoo 4G 12:10 PM mybb.qu.edu.qa different)? Comment on the value you found

Question

oo Ooredoo 4G 12:10 PM mybb.qu.edu.qa different)? Comment on the value you found 4- The instructor decides to nominate 5 students randomly to deliver a presentation n ext class, How many groups (of five students) are possible? What is the probability that you are among the selected students? Problem#2 A firm has ordered a batch of identical electronic device from 4 different suppliers with the following distribution: 35% from supplier 1, 20% from supplier 2, 30% from supplier 3, and 15% from supplier 4. The historical data shows that 8% of supplier's items, 6% of supplier2's items, 4% of supplier3's items, and 10% of supplier 4 items are defective 1-What is the probability that a randomly selected device is coming from supplier 3 or from supplier 2? 2-What is the probability that a randomly selected device is coming from supplier 3 and is defective? 3- What is the probability that a randomly selected device is defective? 4-If an item is selected at random and it is found defective, what is the probability that it is coming from supplier 3?

Explanation / Answer

P(supplier 1) = 0.35

P(supplier 2) = 0.2

P(supplier 3) = 0.3

P(supplier 4) = 0.15

P(defective | supplier 1) = 0.08

P(defective | supplier 2) = 0.06

P(defective | supplier 3) = 0.04

P(defective | supplier 4) = 0.1

1) P(supplier 3 or 2) = P(supplier 2) + P(supplier 3)

= 0.3 + 0.2

= 0.5

2) P(supplier 3 and defective) = P(defective | supplier 3) * P(supplier 3)

= 0.04 * 0.3

= 0.012

3) P(defective) = P(defective | supplier 1) * P(supplier 1) + P(defective | supplier 2) * P(supplier 2) + P(defective | supplier 3) * P(supplier 3) + P(defective | supplier 4) * P(supplier 4)

= 0.08 * 0.35 + 0.06 * 0.2 + 0.04 * 0.3 + 0.1 * 0.15

= 0.067

4) P(supplier 3 | defective) = P(defective | supplier 3) * P(supplier 3) / P(defective)

= 0.04 * 0.3 / 0.067

= 0.1791

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