Exercise 2.2The data in Table 2.1 concern the geyser s geyser alternates periods
ID: 3329846 • Letter: E
Question
Exercise 2.2The data in Table 2.1 concern the geyser s geyser alternates periods of eruption, which typically last of dormaney, which are considerably 21 pr of 60 sampled dormant periods. the geysiraily last Old Faithful in Yellowstone National Park from 1.5 to 4 minutes, with periods oger Table 2.1 presents the duration, (say X), in minutes 42 | 45 | 49 I sol 51 T-5151 53 53 55 55 56 56 57 58 68 69 70 71 75 80 84 93 CLE 74 79 82 82 82 83 72 73 73 75 1 75 | 76176 76 176 80 84 79 80 1-84 80 | 85 86 86.186.1 88 | 90 | 91 81 In the following table. Durationx DGC scrambled duration, say Y as. Scrambled Duration 40 2o2s 62345 337S sec3105 31s_ 31451324 132YS 3285 333-3375 337 33751 3y20 | 3420 | 3 u zo | 34201 3420 3 3660 3615 3610 360 61 3735 3135 310 378013760133870 367013870 39eeltosolyoftslHoExplanation / Answer
a) X bar = 4271/60= 71.18
b) Y bar= 192109/60= 3201.81
c) Y bar/ X bar = 3201.81/71.18= 44.98
d) Median of 60 dormant period= 75
e) Median of 60 scrambled duration= 3375
f) Ratio= Median New/Median= 3375/75= 45
g) Mode value of 60 period= 76
f) Modal value of 60 scrambled duration= 3420
I) Ratio= Mode New/Mode= 3420/76= 45
Conclusion Ratio of Median and Ratio of modes are equal.
j) Variance of X= 178.45
Standard deviation of X= 13.35
Coefficient of variation= STD/ xbar= 0.1875= 18.75%
These are statistic because X is 60 sampled dormant period.
Conclusion Coefficient of variation is only 18.75% of data
K) variance of Y= 352515.91
Standard deviation of Y= 593.73
Coefficient of variation of Y= STD*100/Y bar= 593.73* 100 /3201.81 = 18.54
I) Variance of Y/ Variance of X= 1975.43
STD of Y/ STD of X= 44.47
Coefficient of variation of Y/ Coefficient of variation of X
= 1.01
Ratio of coefficient of variation of Y and X is 1.01
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.