According to a spring 2009 poll of more than 2,200 college students across 40 co
ID: 3329533 • Letter: A
Question
According to a spring 2009 poll of more than 2,200 college students across 40 colleges and Universities, 80 percent of students reported feeling stressed on a daily basis. Assume that the true proportion of students who feel stressed on a daily basis is 80% 1. Find two z scores that contain the central 95% of the standard normal distribution. Lower 2. Suppose you take a survey of 111 college students. Between what two values will the sample proportion of students in the survey who feel stressed be between 95% of the time? Lower: Upper: Upper: Submit Answer Save Progress Practice Another VersionExplanation / Answer
1. Two z scores will be: -1.96, 1.96
2. The statistical software output for 95% confidence interval is:
One sample proportion summary confidence interval:
p : Proportion of successes
Method: Standard-Wald
95% confidence interval results:
Hence,
Lower = 0.726
Upper = 0.874
Proportion Count Total Sample Prop. Std. Err. L. Limit U. Limit p 88.8 111 0.8 0.03796632 0.72558738 0.87441262Related Questions
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