Based on this method I need to came up with my own problem and I don’t know how.

Question

Based on this method I need to came up with my own problem and I don’t know how.. I have to make one up. Slide Show 2 Tell me what y ign in : 1 : 2n . Iift Text Direct Shape Fl Shape Outline . Shape Effects- D Find 1 Align Text Replace . Convert to SmartArt-%( ) | Arrange Quick Styles . [> Select . Paragraph Measurement of Growth Rate and Generation Time Copyright © the McGraw-Hil Companies Inc Permission required for reproduction or display Calculation of the mean growth rate Calculation of the mean generation (doubling) time If a population doubles, then Let No - the initial population number N, the population at time t n-the number of generations in timet N: = 2N Substitute 2N, into the mean growth rate equation and solve for For populations reproducing by binary fission log (2N°) _ log N, = log 2 + log NO-logN, 0.301g 0.301g Solving for n, the number of generations, where all logarithms are to the base 10, log N,- log No+n log 2, and log N-log No log N-log No The mean generation time is the reciprocal of the mean growth rate. n= g 2 0.301 The mean growth rate (a) is the number of generations per unit time (#). Thus k to add notes ] e@ na

Explanation / Answer

If one starts with 10,000 (10 ^4 ) cells in a culture that
has a generation time of 2 h, how many cells will be in the
culture after 6h, and 8h?
Use the equation Nt= N0*2^n

, where N0 is the initial number
of cells, n is the number of generations, and X is the number
of cells after n generations.
After 6h, n =
6h/2 h per generation -
3 generations:
Nt= 2^n*N0
= 2^3*10^4= 8.0*10^4
After 8h, n = 8h/2h
4 generations:

Nt= 2^n*N0
= 2^4* 10^4 cells

= 16*10^4 cells

Please Note: This is on my personal perspective. I hope it will help you.

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