Listed below are the top 10 annua general? al salaries (in millions of dolars) o
ID: 3326677 • Letter: L
Question
Listed below are the top 10 annua general? al salaries (in millions of dolars) of TV personalities. Find the range. varlance, and standard de 3837 35 27 19 18 16 13 126 118 The range of the sample data is million (Type an integer or a decimal ) The variance of the sample data is (Round to two decimal places as needed ) The standard deviation of the sample data is million. Round to two decimal places as needed) Is the standard deviation of the sample a good estimate of the variation of salaries of TV personalities in general? 0 A. No, because there is an outlier in the sample data O B. No, because the sample is not representative of the whole population C. Yes, because the standard deviation is an unbiased estimator D. Yes, because the sample is random.Explanation / Answer
range = Maximum - Minimum = 38 - 11.8 = 26.2
Mean = Sum of observations/ Count of observations
Mean = (38 + 37 + 35 + 27 + 19 + 18 + 16 + 13 + 12.6 + 11.8 / 10) = 22.74
Variance
Step 1: Add them up
38 + 37 + 35 + 27 + 19 + 18 + 16 + 13 + 12.6 + 11.8 = 227.4
Step 2: Square your answer
227.4*227.4 =51710.76
…and divide by the number of items. We have 10 items , 51710.76/10 = 5171.076
Set this number aside for a moment.
Step 3: Take your set of original numbers from Step 1, and square them individually this time
38^2 + 37^2 + 35^2 + 27^2 + 19^2 + 18^2 + 16^2 + 13^2 + 12.6^2 + 11.8^2 = 6175
Step 4: Subtract the amount in Step 2 from the amount in Step 3
6175 - 5171.076 = 1003.924
Step 5: Subtract 1 from the number of items in your data set, 10 - 1 = 9
Step 6: Divide the number in Step 4 by the number in Step 5. This gives you the variance
1003.924 / 9 = 111.5471
Step 7: Take the square root of your answer from Step 6. This gives you the standard deviation
10.5616
No, because the sample is not representative of the whole population.
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