An insurance company crashed four cars in succession at 5 miles per hour. The co

Question

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $411, $470, $419, $236 . Compute the range, sample variance, and sample standard deviation cost of repair.
The range is $ nothing. An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $411, $470, $419, $236 . Compute the range, sample variance, and sample standard deviation cost of repair.
The range is $ nothing. An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $411, $470, $419, $236 . Compute the range, sample variance, and sample standard deviation cost of repair.
The range is $ nothing.

Explanation / Answer

Sol:

Range=highest-lowet

=470-236

=234

Std deviation

variance=102.0686*102.0686

=10418

cost(x) xbar x-xbar (X-xbar)^2 411 384 27 729 470 384 86 7396 419 384 35 1225 236 384 -148 21904 31254 standarddeviition=sqrt(31254/4-1) 102.0686 standard deviation=102.0686

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