My study guide has 0.0548 as the answer and I have to use a table instead of exc

Question

My study guide has 0.0548 as the answer and I have to use a table instead of excel if the z score is necessary for this problem. Use the following information to answer Questions 24-28. A researcher is interested in the lengths of Salvelinus fontinalis (brook trout), which are known to be approximately Normally distributed with mean 80 centimeters and standard deviation 5 centimeters. To help preserve brook trout populations, some regulatory standards need to be set limiting the size of fish that can be caught.

Explanation / Answer

Mean is 80 and s is 5

z is given as (x-mean)/s

P(x<72)=P(z<(80-72)/5)=P(z<1.6)

from normal distribution table we get 0.9452

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