-13. Suppose that a 99% confidence interval for difference P-Ps between the fhe

Question

-13. Suppose that a 99% confidence interval for difference P-Ps between the fhe poltorise mmnd els C, Which of who are of men the following statements is correct? We are 99% confident that the proportion of alcoholics is between .02 and .09. a. b. We are 99% confident that teproportion of men in California who are alcoholics is betwcen 02 and 09 larger than the proportion of women in California who are c. We can conclude that the population proportions may be equal. d. We are 99% confident that a minority in California residents are alcoholics. 14, The p-value for testing Ha: =100 against H. # 100 s0001. Tis indicates that 100. There is strong evidence that There is stron unusual to obtain data such as those observed The probability that -100 is .001 The probability that _ 100 is the significance leveluually taken to be 05. a. b. gevidence that #100, since if wore equal to 100, it would be c. d. 15. In a multiple regression analysis, ifthe normal probability plot of the residuals then it can be concluded that the assumption of normality is not valid a. b. c. d. is a straight line has the shape of a symmetric bell shaped curve is greatly curved has the shape of a parabola that opens upward PART II 16. (15 points) An analysis was performed relating age and gender to predict systolic blood pressure (sbr. The scatter plot appears below. Note that Gender = 0 (circles) is for Fennales and Gender = 1 (squares) is for males. Eind

Explanation / Answer

13> option b
here the confidence interval is of p1-p2 , where p1 is the proprtion of males.

14>option b
generally the null hypothesis is rejected when the p-value is less than the level of significance.
here p-value is 0.001 which is less than the level of significance which is usually either 0.05 or 0.01.

15>option c
normal probability plots are used to check whether the data came from a normal distribution or not.
if it is a straight line we conclude it came from a normal distribution and viceversa.
it is used to check the normality of the data.

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