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7, Refer to problem A 0.19 8.0.35 C 0.42 D. 0.62 E.0.26 #6 and find the Probabil

ID: 3324241 • Letter: 7

Question

7, Refer to problem A 0.19 8.0.35 C 0.42 D. 0.62 E.0.26 #6 and find the Probability (Next arrival takes longer than 5 minutes). and Lifetimes of a certain component are lognormally distributed with parameters 5.(W .Normal(1 , -0.5)) Find the Probability (lifetime-mean). A.0.2 B. 0.4 C.O.5 D. 0.35 E. 0.6 8. Resistors are labeled 100 , where the actual resistances are uniformly distributed on the interval (95,103). Suppose that resistances of different resistors are independent. What is the probability that three out of six resistors have resistance greater than 100 ? A. 0.48 B. 0.38 C. 0.52 D. 0.26 E.0.18

Explanation / Answer

Question

Mean = 1

Std.. deviation = 0.5

Pr(Lifetime >Mean ) = 0.5

Question 9

Here,

f(x) = 1/ (103 - 95 ) = 1/8 ;

F(X) = (x - 95)/ 8 ; 95 < X < 103

so

Pr(X > 100) = 1- F(100) = 1 - (103 - 100)/ 8 = 0.625

So,

now n = 6 ; p = 0.625

Pr(Y = 3; 6; 0.625) = BIN (Y = 3; 6; 0.625) = 6C3 (0.625)3 (0.375)3 = 0.2575 or 0.26

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