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l le Tainge Ih miles) are shown in the table below TREATMENTS Fuel Fuel 2 Fuel 3

ID: 3322615 • Letter: L

Question

l le Tainge Ih miles) are shown in the table below TREATMENTS Fuel Fuel 2 Fuel 3 Fuel 4 Fuel 5 B. Launcher A| 45.9 | 52.2 | 47.3 | 57.6 45.6 Launcher B 46.050.1 39.9 51.0 53.2 Launcher C 45. 55.3 42.1 56.9 49.9 Launcher D 51.148.7 52. 43.5 49.2 lain why you advised them to not use a one-way ANOVA. et scientists note that the data are laid out in a rectangular grid "just like a contingency table " When they ask if you'll use the chi-squared test, why you tell them that the chi-squared isn't lowing shows a partially completed analysis of variance. Fill in all the blanks. Source of Sum of Squaresfreedonm ofMean Square Critical vala variationSum of Squares Degrees of 3.49 locks 11.49 3.26 reatments135.74 Error 23.4 Total ich of the following have a significant effect? Circle your answer. i. Fuel only ii Launcher only ii Both fuel and launcher iv. Neither fuel nor launcher YOU CANNOT SKIP THIS PROBLEM

Explanation / Answer

Result:

This is a Randomized block design. We have to reduce the experimental error among observations of the same treatment by accounting for the differences among blocks. So this is not one way ANOVA.

Chi square test is used for the two way table of frequencies. Chi square test is not applicable for this given data because the given numbers are continuous score for each treatments.

Source

SS

Df

MS

F

F critical

Blocks

11.49

3

3.83

0.1637

3.49

Treatments

135.74

4

33.935

1.4502

3.26

Error

280.8

12

23.4

Total

428.03

19

calculated F values are < F critical values. Ho is not rejected.

Significance: iv Neither fuel nor launcher.

Source

SS

Df

MS

F

F critical

Blocks

11.49

3

3.83

0.1637

3.49

Treatments

135.74

4

33.935

1.4502

3.26

Error

280.8

12

23.4

Total

428.03

19