21. The number of days per month Linda runs at least five miles has the followin

Question

21. The number of days per month Linda runs at least five miles has the following distribution. Days 0 5 10 15 20 Frequency 0.1 0.2 0.3 0.25 0.15 21a. What is the chance she will run at least 10 days next month? 21b. What is the most likely number of days she will run next year? 21c. What is the average number of days she runs per month? 21d. What is the standard deviation of the number of days she runs per month? 22. Which of the following increases the width of a confidence interval? (CHECK ALL THAT

Explanation / Answer

a)

probability to run at least 10 days =P(X>=10)=P(X=10)+P(X=15)+P(X=20)=0.3+0.25+0.15=0.7

b) mst likely nuber of days =10 as its relative frequency is the highest among all

c)

from above mean =10.75

d)

std deviation =5.9739

y p(y) yP(y) y2P(y) (y-)2 (y-)2P(y) 0 0.1000 0.000 0.000 115.563 11.556 5 0.2000 1.000 5.000 33.063 6.613 10 0.3000 3.000 30.000 0.563 0.169 15 0.2500 3.750 56.250 18.063 4.516 20 0.1500 3.000 60.000 85.563 12.834 total 1 = 10.75 151.250 252.813 2= 35.6875 std deviation=     =    2 = 5.9739

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