5. There were 135 total shuttle flights over the years. 133, flights were onside

Question

5. There were 135 total shuttle flights over the years. 133, flights were onsidered successful and 2 were deemed unsuccessful. Given this binomial istribution: (a) What is the probability that a shuttle flight chosen a random was a successful flight? 132 (b) What is the mean of successful shuttle flights from a sample of 50 flights? (c) What is the variance of successful shuttle flights from a sample of 50 flights? (d) What is the standard deviation of successful shutle fights from a sample of 50 flights? (e) What is the mean of successful shuttle flights from a sample of 64 flights? () What is the variance of successful shuttle flights from a sample of 20 lights? (g) What is the standard deviation of successful shuttle flights from a sample of 98 flights?

Explanation / Answer

5.
a.
probability that a shuttle flight chosen at a random was successful flight is 133/135 =0.98518
b.
mean of successful flights from a sample 0f 50 flights = n*P = 50*0.98518 =49.259
c.
variance of successful flights from a sample of 50 flights = n*P(1-p) =49.259*(1-0.98518) =0.7300
d.
standard deviation of successful flights from a sample of 50 flights = sqrt(n*P(1-p))= sqrt(0.73)=0.8544
e.
mean of successful flights from a sample 0f 64 flights = n*P = 64*0.98518 =63.051
f.
variance of successful flights from a sample of 20 flights = n*P(1-p) = (20*0.98518)(1-0.98518)=0.292
g.
standard deviation of successful flights from a sample of 98 flights = sqrt(n*P(1-p)) =sqrt(98*0.98518(1-0.98518) =1.196

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