During special events, such as Mavericks games, or Cowboys games, policemen are
ID: 3320582 • Letter: D
Question
During special events, such as Mavericks games, or Cowboys games, policemen are assigned to various intersections to speed up the flow of traffic and reduce congestion. To determine if there were any differences among the three busiest intersections needing police supervision, the number of vehicles passing through each of the three intersections was recorded for a 30 minute period over the course of six special event occasions. (Assume normal distributions with equal variances.)
An Anova One-Way test was run on this data with the following results obtained:
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Intersectin 1
6
2690
448.3333
2416.667
Intersectin 2
6
2710
451.6667
2776.667
Intersectin 3
6
2460
410
1610
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
6433.333
2
3216.667
1.418422
0.272
3.68
Within Groups
34016.67
15
2267.778
Total
40450
17
Do these data provide sufficient evidence to indicate that differences exist, at the 5% significance level, in the average number of vehicles passing through the three intersections? (note: the word "intersection" has been abbreviated)
Do not reject the null: there is not sufficient evidence to conclude that differences exist in the average number of vehicles passing through the three intersections.
Reject the null; there is sufficient evidence to conclude that differences exist in the average number of vehicles passing through the three intersections.
Reject the null; there is not sufficient evidence to conclude that differences exist in the average number of vehicles passing through the three intersections.
not enough information to make a conclusion/decision.
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Average
Variance
Intersectin 1
6
2690
448.3333
2416.667
Intersectin 2
6
2710
451.6667
2776.667
Intersectin 3
6
2460
410
1610
ANOVA
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
6433.333
2
3216.667
1.418422
0.272
3.68
Within Groups
34016.67
15
2267.778
Total
40450
17
Explanation / Answer
P - value from the ANOVA table = 0.272
Since this p - value is greater than level of significance 0.05,
Do not reject the null: there is not sufficient evidence to conclude that differences exist in the average number of vehicles passing through the three intersections.
Option A is correct.
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