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Do Homework- Brooke Allen - Google Chrome llurn.ecollege Secure https://www.mathd.com/Student/PlayerHomework.aspx?homeworkId=449511082&ques; MATH 2300-010 Fall 2017 Homework: Chapter 6 Homework Score: 0 of 1 pt 24 of 29 (16 complete) 6.3.93 A variable is normally distributed with mean 4 and standard deviation 2 a. Determine the quartiles of the variable b. Obtain and interpret the 90th percentile C. Find the value that 65% of all possib e values of the variable exceed. d. Find the two values that divide the area under the corresponding normal curve into a Y. middle area of 0 95 and two outside areas of 0.025. Interpret the answer Click here to view page 1 of the standard normal distribution table a, Q1 = (Round to two decimal places as needed )

Explanation / Answer

a) here for 25 th percentile z =-0.6745

therefore Q1=mean+Z*Std deviation =2.65

for 50 th percentile z =0

therefore Q2=mean+Z*Std deviation =4

for 75 th percentile z =0.6745

therefore Q3=mean+Z*Std deviation =5.35

b)

for 90th percentile ; z=1.2816

therfore corresponding value =mean+Z*Std deviation =6.56

90% vlaues are below 6.56

c)

for 35 percentile ; z=-0.3853

therfore corresponding value =mean+Z*Std deviation =3.23

d)

value are -1.96 and 1.96

2)

a) P(16<X<17)=P((16-17.92)/1.86<Z<(17-17.92)/1.86)=P(-1.0323<Z<-0.4946)=0.3104-0.1510=0.1595

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