Do Homework Correy Johnson Google Chrome rHomework aspx?homeworkld 420934222&que

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Do Homework Correy Johnson Google Chrome rHomework aspx?homeworkld 420934222&questionld; 5&flushed; false&cld; 4414516&centerwin; yes Secure l https://www.mathxl.com/Student/Player MTH 140 NN 201702 DTR Homework: Unit 4 Assignment 1 Score: 0 of 1 pt HW Score: 49.1%, 9.82 of 20 pts 15 of 20 (12 complete) 6.3.11 Question Help In a survey of 633 males ages 1864, 399 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. The 90% confidence interval for the population proportion p is (Round to three decimal places as needed.) Enter your answer in the edit fields and then click Check Answer 3 parts

Explanation / Answer

Using a calculator and a 1 proportion Z-interval, the point estimate is 399/633=0.630

proportion(p) =399/633=0.630
:
standard error(se) = square root( 0.630 * (1-0.630) / 630 ) = 0.0192
:
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90% confidence interval(CI)
:
alpha(a) = 1 - (90/100) = 0.10
critical probability(p*) = 1 - (0.10/2) = 0.95
degrees of freedom(df) = 633 -1 = 632
critical value(use t statistic calculator) = 1.647
margin of error(me) = 1.647 * 0.0192 = 0.0316
90% ci is 0.630 + or - 0.032, that is, (0.594, 0.658)
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:
95% ci
:
a = 1 - (95/100) = 0.05
p* = 1 - (0.05/2) = 0.975
df = 632
cv = 1.964
me = 1.964 * 0.0192 = 0.0377
95% ci is 0.30 + or - 0.038, that is, (0.588, 0.664)

so the value answer is 0.630

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