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A government organization is examining the effectiveness of a program intended to shorten security lines at airports for "trusted travelers". For comparison purposes, a sample was obtained of the time in seconds it took passengers not on the program to pass through security at a certain international airport. The accompanying data contain the results. Complete parts a through c below EEl Click the icon to view the security time data. a. Calculate the sample mean and the sample standard deviation for this sample of passenger times. The sample mean is seconds. (Round to two decimal places as needed.) The sample standard deviation is seconds. (Round to two decimal places as needed.) a e % confidence rt timate or he b. Assume that the distribution of t me required to pass through security at his arport s normally stbuted. Use he sam le da a average time required to pass through security co s ut va The 95% confidence interval is seconds (Round to two decimal places as needed.) seconds. c. What is the margin of error for the confidence interval constructed in part b? e: ± seconds (Round to two decimal places as needed.)

Explanation / Answer

Sample mean = 256.1231

Sample std. dev. = 80.6051

ME = +/- 13.85603

CI for 95% n 130 mean 256.1230769 z-value of 95% CI 1.9600 std. dev. 80.60507759 SE = std.dev./sqrt(n) 7.06953 ME = z*SE 13.85603 Lower Limit = Mean - ME 242.26705 Upper Limit = Mean + ME 269.97911 95% CI (242.267 , 269.9791 )

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