Would you accept the following simple linear regression model? Why or why not? (
ID: 3319034 • Letter: W
Question
Would you accept the following simple linear regression model? Why or why not? (5 points)
Call:
lm(formula = casual ~ temp, data = dnum)
Residuals:
Min 1Q Median 3Q Max
-1005.4 -343.4 -142.5 131.1 2521.8
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) -161.35 61.59 -2.62 0.00899 **
temp 2037.86 116.63 17.47 < 2e-16 ***
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Signif. codes:
0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 576.8 on 729 degrees of freedom
Multiple R-squared: 0.2952,Adjusted R-squared: 0.2942
F-statistic: 305.3 on 1 and 729 DF, p-value: < 2.2e-16
Explanation / Answer
YOu have to look at the p value to see if the model is significant or not
p value = 2.2e-16
This p value will be smaller than any significance level we choose
If p < alpha we reject null hypothesis and model would be accpted. Though R^2 value is low
Thus, The model is significant
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