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Would you accept the following simple linear regression model? Why or why not? (

ID: 3319034 • Letter: W

Question

Would you accept the following simple linear regression model? Why or why not? (5 points)

Call:

lm(formula = casual ~ temp, data = dnum)

Residuals:

    Min      1Q Median      3Q     Max

-1005.4 -343.4 -142.5   131.1 2521.8

Coefficients:

            Estimate Std. Error t value Pr(>|t|)    

(Intercept) -161.35      61.59   -2.62 0.00899 **

temp         2037.86     116.63   17.47 < 2e-16 ***

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Signif. codes:

0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 576.8 on 729 degrees of freedom

Multiple R-squared: 0.2952,Adjusted R-squared: 0.2942

F-statistic: 305.3 on 1 and 729 DF, p-value: < 2.2e-16

Explanation / Answer

YOu have to look at the p value to see if the model is significant or not

p value = 2.2e-16

This p value will be smaller than any significance level we choose

If p < alpha we reject null hypothesis and model would be accpted. Though R^2 value is low

Thus, The model is significant

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