DHW10.pdf d .> Apps Introduction to ElectWatch Kansas City Ch HW10.pdf Secure ht
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DHW10.pdf d .> Apps Introduction to ElectWatch Kansas City Ch HW10.pdf Secure https://learn.wsu .edu/bbcswebdav/pid-2291123-dt-content-rid-35833273 1/courses/2017-FALL-PULLM-STAT-360-1740-LEC/Hw10.pdf 1. A new design for the braking system on a certain type of car has been proposed. For the current system, the true average braking distance at 40 mph under specified conditions is known to be 120 ft. It is proposed that the new design be implemented only if sample data strongly indicates a reduction in true average braking distance for the new design. The summary statistics and the qq-plot is given below mean sd IQR 0% 25% 50% 75% 115.0633 5.1679 6.675 101.7 111.6 115.15 118.275 100% n 123.4 30 Carry out a hypothesis test to decide whether the new design should be implemented. Use significance level of 0.05. (Follow the 4-step procedure for full credits.) (8pts) Verify if the test you use is appropriate. (2pts) A. B. 12-58 PM Type here to search 127/2017Explanation / Answer
Question 1
Part A
Here, we have to use one sample t test for population mean.
The null and alternative hypothesis for this test is given as below:
H0: µ = 120 versus Ha: µ < 120
We assume = 0.05
We are given
Xbar = 115.0633
S = 5.1679
n = 30
df = n – 1 = 30 – 1 = 29
Lower critical value = -1.6991 (by using t-table or excel)
Test statistic formula is given as below:
t = (Xbar - µ) / [S/sqrt(n)]
t = (115.0633 – 120) / [5.1679 / sqrt(30)]
t = -4.9367/0.9435
t = -5.2322
P-value = 0.0000 (by using t-table)
= 0.05
P-value < = 0.05
So, we reject the null hypothesis H0 that average braking distance is 120 ft.
There is sufficient evidence to conclude that average braking distance is less than 120 ft.
New design should be implemented.
Part B
We have to check above test by using excel. Excel output for this test is given as below:
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
120
Level of Significance
0.05
Sample Size
30
Sample Mean
115.0633
Sample Standard Deviation
5.1679
Intermediate Calculations
Standard Error of the Mean
0.9435
Degrees of Freedom
29
t Test Statistic
-5.2322
Lower-Tail Test
Lower Critical Value
-1.6991
p-Value
0.0000
Reject the null hypothesis
We get same results as per above.
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
120
Level of Significance
0.05
Sample Size
30
Sample Mean
115.0633
Sample Standard Deviation
5.1679
Intermediate Calculations
Standard Error of the Mean
0.9435
Degrees of Freedom
29
t Test Statistic
-5.2322
Lower-Tail Test
Lower Critical Value
-1.6991
p-Value
0.0000
Reject the null hypothesis
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