4. Bibliotherapy is a common tool to use with children who have a hard time bond
ID: 3318112 • Letter: 4
Question
4. Bibliotherapy is a common tool to use with children who have a hard time bonding with a therapist and opening up during therapy sessions. Dr. Contos wants to examine if children who participate in bibliotherapy (M=16.48, SD=2.67) score lower on levels of anxiety (0-25) than children who participate in play therapy (M=18.11, SD=2.58). She interviews 25 children in each group for a total of 50 children. (Total 29 pts) A. What are the independent and dependent variables and how are each scaled (1 pt each; Total 4 pts)? Independent:________________________ Scaling:_____________________________ Dependent:__________________________ Scaling:_____________________________ B. What test should Dr. Contos use (4 pts)?__________________________________________________ C. Why that test (2 pts)? D. What are the null and alternative hypotheses for that test (4 pts)? E. What are that tests assumptions (3 pts)? F. What are the df (2 pts)?________________________ G. What is the critical value for p=.05 (2 pts)? _________________________ H. If Audi calculates a test statistic of 4.76, should they (2 pts)? Retain H0 Reject H0 I. Interpret the findings (6 pts): **Can anyone answer these with shown work, please?**
Explanation / Answer
A. What are the independent and dependent variables and how are each scaled
Answer : Independent : "Type of therapy used"
Dependent : Anxiety level score
B. What test should Dr. Contos use
Answer : A student's t test for two independent saple with equal variances.
C. We will use this test because population standard deviation is unknown here and the samples are independent and of different groups.
D. Null hypothesis : H0 : The anxiety level among Children who particaipate in bibilotherapy is equal to the anxiety level among children who participate in play therapy. 1 = 2
ALternative Hypothesis : Ha : The anxiety level among Children who participate in bibilotherapy is lesser than the anxiety level among children who participate in play therapy. 1 < 2
E. Assupation of test
(i) Samples are independently drawn.
(ii) The samples are normally distributed.
(iii) NO outliers or homogeneity of variances of two groups.
F. dF = 25 + 25 - 2 = 48
G. Here critical value for p = 0.05 is
as it is one tailed test.
tcritical = t0.05,48 = 1.6772
H. here
t = 4.76
so we shall reject the null hypotheesis. as t > tcritical
I . Here we can declare that The anxiety level among Children who participate in bibilotherapy is lesser than the anxiety level among children who participate in play therapy.
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