i safari File Edit View History Bookmarks Window Help 55% CO Wed 4:28 PM a What

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i safari File Edit View History Bookmarks Window Help 55% CO Wed 4:28 PM a What Are The Correct Answers?? Thank You!! Connect Chapter 9 6 Saved Help Save & Exit Submit 41 PM Check my work 5 A population is estimated to have a standard deviation of 14, we want to estimate the population mean within 2, with a 98% level of confidence een Shot 12..17.44 PM How large a sample is required? (Round up your answer to the next whole number.) points required is een Shot 12...20.32 PM eBook Print Reterences een Shot 12...0.38 PM Reference links cen Shot 2...22.25 PM een Shot 2...22.27 PM een Shot 12...4.44 PM

Explanation / Answer

z for 98% confidence is 2.33

here margin of error ME is 2

standard deviation s is 14

thus ME=z*s/sqrt(N)

2=2.33*14/sqrt(N)

or N is (16.31)^2=266.02 or 267

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