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ID: 3315712 • Letter: D

Question

Do Homework - Chase Huckeby Google Chrome Secure ht| Secure! https://www.mat PlayerHomework.aspx? ld 4420642198questionld 1&flushed-false;&cld; 46359128 centerwinzyes Econ 2843: Elements of Statistics (Fall 2017, section 3) Chase Huckeby | 12/4/17 6:29 PM Homework: H.W, 9.3 Score: 0 of 1 pt 9.3.51 Save home/ study 6 of 6 (0 complete) HW Score: 0%, 0 of 6 pts Question Help The waiting time to check out of a supermarket has had a population mean of 10.23 minutes. Recently, in an effort to reduce the waiting time, the supermarket has experimented with a system in which there is a single waiting line with multiple checkout servers. A sample of 80 customers was selected, and their mean waiting time to check out was 9.42 minutes with a sample standard deviation of 5.3 minutes. Complete parts (a) through (d). ick a. At the 0.05 level of significance, using the critical value approach to hypothesis testing, is there evidence that the population mean waiting time to check out is less than 10.23 minutes? What are the null and alternative hypotheses for thistest? A. HOP2 10.23 D. Ho : 10.23 E. Ho: > 10 23 H1 : 10.23 ° C. Ho-p29.42 H 1 :

Explanation / Answer

9.3.51.

Given that,
population mean(u)=10.23
sample mean, x =9.42
standard deviation, s =5.3
number (n)=80
null, Ho: >=10.23
alternate, H1: <10.23
level of significance, = 0.05
from standard normal table,left tailed t /2 =1.664
since our test is left-tailed
reject Ho, if to < -1.664
we use test statistic (t) = x-u/(s.d/sqrt(n))
to =9.42-10.23/(5.3/sqrt(80))
to =-1.367
| to | =1.367
critical value
the value of |t | with n-1 = 79 d.f is 1.664
we got |to| =1.367 & | t | =1.664
make decision
hence value of |to | < | t | and here we do not reject Ho
p-value :left tail - Ha : ( p < -1.367 ) = 0.08776
hence value of p0.05 < 0.08776,here we do not reject Ho
ANSWERS
---------------
null, Ho: >=10.23
alternate, H1: <10.23
test statistic: -1.367
critical value: -1.664
decision: do not reject Ho
p-value: 0.08776
we do not have enough evidence to support the claim that population mean time waiting to check out less than 10.23 minutes

option :A

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