Suppose that 10% of the fieds in a given agricultural area are infested with the

Question

Suppose that 10% of the fieds in a given agricultural area are infested with the sweet potato whitely. One hundred fields in this erea are rendomly selected, and 35 are found to be infested with whitefly (a Assuming that the expe ment satisfies the conditions of the binomial e pe ment, do he data indicate that the proportion infested fields is greater than expected Use thep-value approach, and test using a S% s if cance eve Round your answer to four dec mal places. Null and alternotive HO: -0.1 versus Ha: P , 0.1 o Ho: p 0.1 HO: -0.1 versus Hai p > 0.1 @ Mo: = 0.1 versus Ha: pe 0.1 HO: 0.1 versus Hai -0.1 P-value- ® HO is rejected. There is suticient evidence to indicate that the prop0lan f infested fields !arger than expected. O Ho is not rejected. There is sufficient evidence to indicate that the proportion af infested fields is larger than expected HO is not rejected. There is insufficent evidence bo indicate that the proportion of intested fields is larger than expected. O o is rejected. There is insuffidient evidence to indkcate that the proportion of infested fields is larger than expected What practical of infested ficlds is found to be than 0.10 is this of What practical condlusions might she draw from the results? If the Tha agronomist may determine that because the propartion of infested ields was nat unusual, the samping method wae not randam. The ogranomist may determine thot because the proportion of infested fields was not unusual, no action needs to be taken The egronomist mey determine thet an unusuelly low proportion of infested fields might indicate a contegious disease The agronamist may determine that because the proportion of infested ields was unusual, no action needs to be taken. to the a e The agronamist may determine that an unusuelly high proportion of infested fields indkates a contagious disease

Explanation / Answer

Here all answers are correct. Now i have to calculate p - value

Here standard error of proportion = sqrt ( 0.1 * 0.9 / N) = sqrt (0.1 * 0.9/ 100) = 0.03

Here sample proportion p^ = 35/100 = 0.35

Here Z = (0.35 - 0.10)/ 0.03 = 8.3333

p - value = Pr(Z > 8.3333) = 0.0000

so the proability is exteremly low.

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