/ T8l030 including pro Chapter to estimate values of population parameters This
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/ T8l030 including pro Chapter to estimate values of population parameters This chapter included procedures for finding point estimates, c intervals, and determining sample size required to estimate population following applications apply these methods to a variety of California d parameter h pröportions, means and constructing conf vari ifornia data sets. Exercises (Answers for these exercises are given in Appendix E.) 1. Sample Size California's population in a recent year was reportedas 37,691,912 by the U.S. Census bureau. This makes California the most lated state. Find the sample size required for a survey intended to estimate the percentage of adults in California who use the Internet. Assume a confidence level of95% and a margin oferror of 3.5 percentage points. 2. Evaluating Poll Results A recent news story began with the headline California voters don't back marijuana legalization, poll finds." The poll found that 50% of registered voters were opposed to the legalization of marijuana for recreational use by adults while 46% were in favor. The margin of sampling error of the poll is 3.5 percentage points. Is the claim in the headline supported by the poll findings? 3. Airport Passengers in Santa Ana and San Jose Listed below are numbers of passengers served at airports in Santa Ana and San Jose (based on data from the Department of Transportation). The values are in thousands and they are listed in order for each month of a recent year. Using each of the two samples. construct the two 95% confidence interval estimates of the two population means, then compare the confidence intervals. What do you conc John Wayne San Jose: 707 702 820 775 771 798 824 834 688 732 649 690 741 741 858 812 872 915 936 939 742 775 691 699 4. San Francisco Rainfall Listed below are amounts of rainfall (inches) for tn different months of a recent year in San Francisco. Using each of the two samples, construct the two 95% confidence interval estimates of the pop ula- eans, then compare the confidence intervals. What do you conc tion mExplanation / Answer
1)
margin of error = z-score * standard error
z-score at 95% = 1.96
standard error = sqrt(0.5 * 0.5/n)
margin of error = 1.96 * sqrt(0.5 * 0.5/n) = 3.5%
size of sample n = 784
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