4. 1/3 polnts | Pr evious Answers DevoreStat9 9.E.020 My Notes Ask Your Teacher

Question

4. 1/3 polnts | Pr evious Answers DevoreStat9 9.E.020 My Notes Ask Your Teacher Suppose 1 and 2 are true mean stopping distances at 50 mph or cars of a certain type equipped with to different types of braking systems. The data ollows: m 5 x 114.5, s1 = 5.06, n = 5, y = 129.9, and s2-5.33. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) Does the interval suggest that precise information about the value of this difference is available? Because the interval is so narrow, it appears that precise information is available Because the interval is so wide, it appears that precise information is not available. Because the interval is so wide, it appears that precise information is available Because the interval is so narrow, it appears that precise information is not available. You may need to use the appropriate table in the Appendix of Tables to answer this question. Need Help?Read It Talk to a Tutor

Explanation / Answer

The statistical software output for this problem is:

Two sample T summary confidence interval:
1 : Mean of Population 1
2 : Mean of Population 2
1 - 2 : Difference between two means
(without pooled variances)

95% confidence interval results:

Hence,

95% confidence interval will be:

(- 22.98, - 7.82)

Difference Sample Diff. Std. Err. DF L. Limit U. Limit 1 - 2 -15.4 3.2867157 7.9784776 -22.98274 -7.8172599

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