4. 1/5 points | Previous Answers OSColPhys2016 16.3.WA.019.Tutorial. My Notes A

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4. 1/5 points | Previous Answers OSColPhys2016 16.3.WA.019.Tutorial. My Notes A mass of 0.48 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x(t)-(0.28 m)cos[(12 rad/s)Detine the following (a) amplitude of oscillation for the oscillating mass b) force constant for the spring N/m (c) position of the mass after it has been oscillating for one half a period d) position of the mass one-third of a period after it has been released (e) time it takes the mass to get to the position x0.10 m after it has been released Additional Materials Reading Tutorial

Explanation / Answer

a)

Amplitude

A=0.28 m

b)

From X(t)=0.28Cos(12t)

W=12 rad/s

Force constant

K=mW2=0.48*122

K=69.12 N/m

c)

Period

T=2pi/W =2pi/12 =0.5236 s

Given t=0.5236/2 =0.2618 s

X=0.28Cos(12*0.2618)

X=-0.28 m

d)

t=0.5236/3=0.1745 s

X=0.28Cos(0.1745*12)

X=-0.14 m

e)

=>-0.1=0.28Cos(12t)

12t=Cos-1(-0.1/0.28)=1.936

t=0.1613 s

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