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Bivariate Fit of Capital By Rental 3500 3000 2500 a 2000 1500 1000 500 4 10 12 R

ID: 3313198 • Letter: B

Question

Bivariate Fit of Capital By Rental 3500 3000 2500 a 2000 1500 1000 500 4 10 12 Rental -Linear Fit Linear Fit Capital- -465.2883 + 228.8306 Rental Summary of Fit RSquare RSquare Adj Root Mean Square Error 423.1768 Mean of Response Observations (or Sum Wgts) 0.624992 0.621002 1725.698 96 Lack Of Fit Analysis of Variance Sum of Source Model Error C. Total DF Squares Mean Square FRatio 28054635 156.6610 1 28054635 94 16833387 95 44888022 179078.59 Prob>F t Intercept-465.2883 180.2983 2.58 0.0114 Rental 228.8306 18.28242 12.52

Explanation / Answer

g) Capital= -465.2883+228.8306*Rental

Y'= b0+b1*X

a) if rental value=0

Capital= -465.2883 or b0 dollers and statement is right.

b) if rental= 1000 is b0 dollers

Capital= -465.2883+228.8306*1000= 228365.312, statement is wrong

c) if rental= 1000 is b0 1000dollers

Capital= -465.2883+228.8306*1000= 228365.312

b0 1000= 1000, wrong statement

d) Capital= 0 is b0 is 1000 dollers

0=-465.2883+228.8306*rental=> rental= 2.0333, wrong

e)if rental =0 is b0 1000 dollers

Capital= -465.2883 or b0 dollers

Answer: A

h) Yes, intercept interpretation is if rental unit is zero then predicted capital will be b0 value.

i)With the context of given data, Intercept value is meaning full with R-squared 0.624992 or 62.4992%

and relation ship with output variable t-value is also significant with lessthan 0.05 p-value.

Data is positively correlated that per every additional rental unit, capital value also increases at 228.8306 per unit.