This Question: 1 pt 7 of 15 (12 complete) This Test: 15 pts possible A single ra

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This Question: 1 pt 7 of 15 (12 complete) This Test: 15 pts possible A single random sample of szen a draemnfrom a popuátion that s normany asituted The sample mean i s tound lo be 13, and the sanple a standard deviation, s, is found to be 10 C (a) Construct a 98% confidence interval about if the sample size, n, is 12. (b) Construct a 98% confidence interval about if the sample sze, n, is 29 (c) Construct a 99% confidence interval about it the sample size, n, is 12 (d) Could we have computed the confidence intervals in parts (a-(C) if the population had not been normally distibuted? g) (a) construct a 98% confidence interval about if the sample size, n, is 12 Lower bound Upper bound: Click the icon to view the table of areas under the t distribution. (Use ascending order. Round to one decimal place as needed.) (b) Construct a 98% conndence interval about if the sample sizen. is 29. Lower bound Upper bound wt (Use ascending order. Round to one decimal place as needed) Click to select your answer(s) , Desktop e here to search

Explanation / Answer

a)

b)

c)

d)

Confidence interval cannot be determined if the population is not normally distributed.

CI for 98% n 12 mean 113 z-value of 98% CI 2.3263 std. dev. 10 SE = std.dev./sqrt(n) 2.88675 ME = z*SE 6.71559 Lower Limit = Mean - ME 106.28441 Upper Limit = Mean + ME 119.71559 98% CI (106.2844 , 119.7156 )

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