This Question: 1 pt 40 of 41 This Test: 41 pts... Question Help A clinical trial

Question

This Question: 1 pt 40 of 41 This Test: 41 pts... Question Help A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 600 babies were born, and 330 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective? pRound to three decimal places as needed) Does the method appear to be effective? O Yes, the proportion of girls is significantly different from 0.5. O No, the proportion of girls is not significantly different from 0.5 Click to select your answerls). Save for Later 4 Previous

Explanation / Answer

Solution :

Given that x = 330 , n = 600

=> p = x/n = 330/600 = 0.55

=> q = 1-p = 0.45

=> For 99% confidence interval , Z = 2.576

=> The 99% confidence interval of the proportion is p +/- Z*sqrt(p*q/n)

=> 0.55 +/- 2.576*sqrt(0.55*0.45/600)

=> 0.498 < p < 0.602

=> No , the proportion of girls is not significantly different from 0.5

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