3. Two accounting professors decided to compare the variance of their grading pr
ID: 3309807 • Letter: 3
Question
3. Two accounting professors decided to compare the variance of their grading procedures. To accomplish this, they each graded the same 10 exams, with the following results:
Mean Grade
Standard Deviation
Professor 1
79.3
22.4
Professor 2
82.1
12.0
At the 10% level of significance, what is the decision regarding the null hypothesis?
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Reject the null hypothesis and conclude the variances are different.
Fail to reject the null hypothesis and conclude no significant difference in the variances.
Reject the null hypothesis and conclude the variances are the same.
Fail to reject the null hypothesis and conclude the variances are the same.
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5. the following ANOVA table for three treatments each with six observations:
Source
Sum of Squares
df
Mean square
Treatment
1116
Error
1068
Total
2184
What is the computed value of F?
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7.48
7.84
8.84
8.48
16. An ANOVA procedure is applied to data obtained from four distinct populations. The samples, each comprised of 15 observations, were taken from the four populations. The degrees of freedom for the numerator and denominator for the critical value of F are _______.
Multiple Choice
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4 and 60, respectively
4 and 21, respectively
3 and 59, respectively
3 and 56, respectively
19. Two accounting professors decided to compare the variance of their grading procedures. To accomplish this, they each graded the same 10 exams, with the following results:
Mean Grade
Standard Deviation
Professor 1
79.3
22.4
Professor 2
82.1
12.0
What is the critical value of F at the 0.02 level of significance?
Top of Form
5.85
5.35
6.51
4.03
Mean Grade
Standard Deviation
Professor 1
79.3
22.4
Professor 2
82.1
12.0
Explanation / Answer
3) for test statistic F =(s1/s2)2 =(22.4/12)2 =3.484
for (n1-1=9) and (n2-1=9) degree of freedom and above test stat ; p value =0.077
as p vlaue is less then 0.1 level ;
Reject the null hypothesis and conclude the variances are different.
5)
from above F value =7.84
16)(
degrees of freedom for the numerator =treatment-1= 4-1 =3
degrees of freedom for the denominator =total values -treatment =60-4 =56
3 and 56, respectively
19)
critical value of F at the 0.02 level of significance and (9,9) degree of freedom =5.35
Source Sum of Squares df Mean square F Treatment 1116 2 558 7.84 Error 1068 15 71.2 Total 2184 17Related Questions
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