5 Begin Date: 221/2018 12:01:00 AM- Due Date: 3/1/2018 11:59:00 PM End Date: 5/5
ID: 3309077 • Letter: 5
Question
5 Begin Date: 221/2018 12:01:00 AM- Due Date: 3/1/2018 11:59:00 PM End Date: 5/5/2018 1159.00 PMM (694) Problem 17: A bicyclist starting from rest applies a force of F-401 N to nde his bicycle across flat ground for a distance of d 235 m before encountering a hill making an angle of 8 23 degrees with respect to the horizontal. The bicycle and rider have a mass of m -95 kg combined ©theexpertta.com S8 33% Part (a) How much work, win joules, did the rider do before reaching the hill? Grade Sammary Deductions 1096 Potential 90% ota acos0 atan0 acotan0sinhO 12 3 Amempts remaining (Slt per attempt) detailed view Degrees O Radians 500 596 Feedback Feedback-for '-deduction The anawer provided was not correct. We have recognized the i give up Hists: deduction per hint. Hints remaining2 following Your anwer appears to be off by a factor of 10", where a isan integer value Ensure you hare represented the number in the correct nits n m s Just before the hill, Assume there is no kinetic fiction between the bicycle and the " 3% Part (b) What is the bic cle's speed ground 33% Part (c) If the cyclist starts coasting at the bottom of the hill, what distance, d in meters, does the bike travel up the Incline?Explanation / Answer
a] Before reaching the hill, the work done will be:
W = Fd = 401 x 235 = 94235 J
b]
Acceleration of the bicycle = a = F/m = 401/95 = 4.221 m/s2
initial velocity = u = 0 m/s
use, v2 - u2 = 2ad
=> v = [0 + 2(4.221)(235)]1/2 = 44.54 m/s
c] Now, it is given that Force is made zero [coasting]
deceleration will be:
a = - gsin23 = - 3.8292 m/s2
initial velocity = 44.54 m/s
final velocity at the top of the incline = 0 m/s
again, use v2 = u2 + 2ad
=> 0 = [44.542 - 2(3.8292)d]
=> d = 259.04 m.
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