1. O 3325 points 1 Previous Answers KatzPSE1 27 P007 potential difference of 56.

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1. O 3325 points 1 Previous Answers KatzPSE1 27 P007 potential difference of 56.0 V and capacitor 2 (C2 = 5.10 F) In the figure below, capacitor 1 (C1-21.0 initially has a has none. The switches are then closed simultaneously. 1 C1 (o) Find the final charge on each capacitor after a long time has passed. - Q2-22964 c (b) Calculate the percentage of the initial stored energy that was lost when the switches were closed Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.%

Explanation / Answer

Initial stored energy = 1/2 C1V12 = 1/2 x 21 x 10-6 x 56 x 56 = 0.6914 J

Final charge on C1 , Q1 = 9.47 x 10-4 C

Therefore voltage V1' = Q1/C1 = 45 V

Energy = 1/2 C1V1'2 = 0.5 x 21 x 10-6 x 452 = 0.02126 J

So the percentage of initial stored energy lost = { (0.6914- 0.02126) / 0.6914 } x 100 = 97 %

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